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A number when successively divided by 3,5 and 8 leaves remai [#permalink]
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Question Stats: Hide Show timer StatisticsA number when successively divided by 3,5 and 8 leaves remainders 1,4 and 7 respectively. Find the respective remainders when the order of the divisors is reversed.A. 8,5,3B. 4,2,1C. 3,2,1D. 6,4,2 E. None of above
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Re: A number when successively divided by 3,5 and 8 leaves remai [#permalink]
ankur1901 wrote: A number when successively divided by 3,5 and 8 leaves remainders 1,4 and 7 respectively. Find the respective remainders when the order of the divisors is reversed.A. 8,5,3B. 4,2,1C. 3,2,1D. 6,4,2 E. None of above Another method is finding the first such number. You performed 3 steps: - divide by 3, rem 1, Quotient Q- then divide Q by 5, rem 4, Quotient Q*- then divide Q* by 8, rem 7, Quotient Q**Let's say the quotient (Q**) you obtained when you divided by 8 was 0. So quotient (Q*) you obtained when you divided by 5 must be 7 (to get 7 as remainder). So the number before division (Q) by 5 must be 5*7 + 4 = 39. This must be the quotient (Q) after division by 3. Original number must be 39*3 + 1 = 118When you divide 118 by 8, remainder is 6, quotient is 14When you divide 14 by 5, remainder is 4, quotient is 2When you divide 2 by 3, remainder is 2Answer (D) _________________
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Re: A number when successively divided by 3,5 and 8 leaves remai [#permalink]
ankur1901 wrote: A number when successively divided by 3,5 and 8 leaves remainders 1,4 and 7 respectively. Find the respective remainders when the order of the divisors is reversed.A. 8,5,3B. 4,2,1C. 3,2,1D. 6,4,2 E. None of above A number when successively divided by 3,5,8 leaving remainders 1,4,7 can be written as 3(5(8k+7)+4)+1=>120k+118when this number is dived by 8 i.e (120k+118)/8=15k+14 remainder 6(15k+14)/5=3k+2 remainder 4(3k+2)/3=k remainder 2And D) 6,4,2Hope its clear
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Re: A number when successively divided by 3,5 and 8 leaves remai [#permalink] A number when successively divided by 3,5 and 8 leaves remainders 1,4 and 7 respectively. Find the respective remainders when the order of the divisors is reversed.A. 8,5,3B. 4,2,1C. 3,2,1D. 6,4,2E. None of above My approach would be Three Divisors: 3, 5, 8Three Remain: 1, 4, 7Start from the bottom of the last column i.e. from the third remainder:Go up diagonally and multiply by the second divisor: 5*7 = 35Go down and add the second remainder: 35 + 4 = 39Go up diagonally and multiply by the first divisor: 39* 3 = 117Go down and add the first remainder: 117 + 1 = 118Divide 118 by 8, 5, 3118/8 gives quotient = 14 and remainder = 614/5 gives quotient = 2 and remainder = 42/3 gives quotient = 0 and remainder = 2 Ans is D i.e. 6,4,2
A number when successively divided by 3,5 and 8 leaves remai [#permalink] thanks for the question. What's the source?
Re: A number when successively divided by 3,5 and 8 leaves remai [#permalink]
kusena wrote: ankur1901 wrote: A number when successively divided by 3,5 and 8 leaves remainders 1,4 and 7 respectively. Find the respective remainders when the order of the divisors is reversed.A. 8,5,3B. 4,2,1C. 3,2,1D. 6,4,2 E. None of above A number when successively divided by 3,5,8 leaving remainders 1,4,7 can be written as 3(5(8k+7)+4)+1=>120k+118when this number is dived by 8 i.e (120k+118)/8=15k+14 remainder 6(15k+14)/5=3k+2 remainder 4 (3k+2)/3=k remainder 2And D) 6,4,2Hope its clear Hello, I don't get the red part. Why isn't the number written as 15K + remainder? That's the way we wrote it in the first portion (from which we got 120k+118)Thanks
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Re: A number when successively divided by 3,5 and 8 leaves remai [#permalink]
usre123 wrote: kusena wrote: ankur1901 wrote: A number when successively divided by 3,5 and 8 leaves remainders 1,4 and 7 respectively. Find the respective remainders when the order of the divisors is reversed.A. 8,5,3B. 4,2,1C. 3,2,1D. 6,4,2 E. None of above A number when successively divided by 3,5,8 leaving remainders 1,4,7 can be written as 3(5(8k+7)+4)+1=>120k+118when this number is dived by 8 i.e (120k+118)/8=15k+14 remainder 6(15k+14)/5=3k+2 remainder 4 (3k+2)/3=k remainder 2And D) 6,4,2Hope its clear Hello, I don't get the red part. Why isn't the number written as 15K + remainder? That's the way we wrote it in the first portion (from which we got 120k+118)Thanks Since 15/5=3 and 14/5=2 and gives 4 as remainder. Hence it is 3k+2 remainder 4Posted from my mobile device
Re: A number when successively divided by 3,5 and 8 leaves remai [#permalink] it was silly question. Got it, thanks:-)
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Re: A number when successively divided by 3,5 and 8 leaves remai [#permalink] Hello from the GMAT Club BumpBot!Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________
Re: A number when successively divided by 3,5 and 8 leaves remai [#permalink] 23 Jan 2016, 22:05 |
When a number is divided by 3/5 and 8 successively we get 1/4 and 7 as successive remainders if the order of divisor is reversed then the remainder are?
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