What is the ci on rs 6400 for 2 years compounded annually at 7½% pa

What is the ci on rs 6400 for 2 years compounded annually at 7½% pa

What is the ci on rs 6400 for 2 years compounded annually at 7½% pa
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Question 36 Compound Interest Exercise 14.2

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What is the ci on rs 6400 for 2 years compounded annually at 7½% pa

Answer:

Given,

Time = 2 years

Rate = 7.5 % per annum

Let principal = Rs P

Compound Interest (CI) – Simple Interest (SI) = Rs 360

C.I – S.I = Rs 360

By using the formula,

P [(1 + R/100)^n - 1] – (PTR)/100 = 360

P [(1 + 7.5/100)^2 - 1] – (P(2)(7.5))/100 = 360

P[249/1600] – (3P)/20 = 360

249/1600P – 3/20P = 360

(249P-240P)/1600 = 360

9P = 360 × 1600

P = 576000/9

= 64000

∴ The sum is Rs 64000

Video transcript

hello everybody welcome to leader learning my name is rajna chaudhary and we have to write this statement in the equation form it is written that write equation for the statements for these statements so statement is one fourth of a number x minus g minus four gives four so one fourth of a number x would be one fourth of x that mean the value of this part is 1 by 4 of x then we have to minus 4 from it so let's minus 4 from it so minus 4 and gives gives means is equal to 4 so this is the equation for the statement we can write it like that at the place of off we can write multiply then minus 4 is equal to 4. we can also write it like x upon 4 minus 4 is equal to 4. so this is the form of equation for the statement i hope you understand the method see you in my next video don't forget to like comment and subscribe leader learning channel thank you for watching

What is the ci on rs 6400 for 2 years compounded annually at 7½% pa
What is the ci on rs 6400 for 2 years compounded annually at 7½% pa

1. Find the amount of $ 8000 for 3 years, compounded annually at 5% per annum. Also, find the compound interest.

Solution: Here, P = $ 8000, R = 5 % per annum and n = 3 years. Using the formula A = $ P(1 + R/ 100)ⁿ amount after 3 years = $ {8000 × (1 + 5/100)³} = $ (8000 × 21/20 × 21/20 × 21/20) = $ 9261. Thus, amount after 3 years = $ 9261. And, compound interest = $ (9261 - 8000)

Therefore, compound interest = $ 1261.

2. Find the compound interest on $ 6400 for 2 years, compounded annually at 7¹/₂ % per annum.

Solution: Here, P = $ 6400, R % p. a. and n = 2 years. Using the formula A = P (1 + R/100)ⁿ Amount after 2 years = [6400 × {1 + 15/(2 × 100)}²] = $ (6400 × 43/40 × 43/40) =$ 7396. Thus, amount = $ 7396 and compound interest = $ (7396 - 6400)

Therefore, compound interest = $ 996.

Case 2: Let principal = $ P, time = 2 years, and let the rates of interest be p % p.a. during the first year and q % p.a. during the second year.

Then, amount after 2 years = $ {P × (1 + P/100) × (1 + q/100)}. This formula may similarly be extended for any number of years.

1. Find the amount of $ 12000 after 2 years, compounded annually; the rate of interest being 5 % p.a. during the first year and 6 % p.a. during the second year. Also, find the compound interest.

Solution: Here, P = $12000, p = 5 % p.a. and q = 6 % p.a. Using the formula A = {P × (1 + P/100) × (1 + q/100)} amount after 2 years = $ {12000 × (1 + 5/100) × (1 + 6/100)} = $ (12000 × 21/20 × 53/50) =$ 13356 Thus, amount after 2 years = $ 13356 And, compound interest = $ (13356 – 12000)

Therefore, compound interest = $ 1356.

Case 3: For example suppose time is 2³/₅ years then,

Amount = P × (1 + R/100)² × [1 + (3/5 × R)/100]

1. Find the compound interest on $ 31250 at 8 % per annum for 2 years. Solution Amount after 2³/₄ years

Solution: Amount after 2³/₄ years = $ [31250 × (1 + 8/100)² × (1 + (3/4 × 8)/100)] = ${31250 × (27/25)² × (53/50)} = $ (31250 × 27/25 × 27/25 × 53/50) = $ 38637. Therefore, Amount = $ 38637, Hence, compound interest = $ (38637 - 31250) = $ 7387.

Let principal = $ P, rate = R% per annum, time = a years.

Suppose that the interest is compounded half- yearly.

Then,

rate = (R/2) % per half-year, time = (2n) half-years, and amount = P × (1 + R/(2 × 100))²ⁿ

Compound interest = (amount) - (principal).

1. Find the compound interest on $ 15625 for 1¹/₂ years at 8 % per annum when compounded half-yearly.

Solution: Here, principal = $ 15625, rate = 8 % per annum = 4% per half-year, time = 1¹/₂ years = 3 half-years. Amount = $ [15625 × (1 + 4/100)³] =$ (15625 × 26/25 × 26/25 × 26/25)= $ 17576. Compound interest = $ (17576 - 15625) = $ 1951.

2. Find the compound interest on $ 160000 for 2 years at 10% per annum when compounded semi-annually.

Solution: Here, principal = $ 160000, rate = 10 % per annum = 5% per half-year, time = 2 years = 4 half-years. Amount = $ {160000 × (1 + 5/100)⁴} =$ (160000 × 21/20 × 21/20 × 21/20 × 21/20) compound interest = $ (194481- 160000) = $ 34481.

Compound Interest by Using Formula, when it is calculated Quarterly

Interest Compounded Quarterly

Then,

rate = (R/4) % Per quarter, time = (4n) quarters, and amount = P × (1 + R/(4 × 100))⁴ⁿ

Compound interest = (amount) - (principal).


Page 2

In 8th grade math practice you will get all types of examples on different topics along with the solutions. 8th grade math worksheets are arranged in such a way that students can learn math while practicing it step by step.

Keeping in mind the mental level of child in 8th grade, every efforts has been made to introduce new concepts in a simple language, so that the child understands them easily. The difficulty level of the problems has been reduced and mathematical concepts have been explained in the simplest possible way. Each topic contains a large number of examples to understand the applications of concepts.

In 8th grade math test we need to learn Rational Numbers, Exponents, Square and Square Roots, Cubes and Cube roots, Operations on Algebraic Expressions, Factorization, Linear Equations, Profit and Loss, Compound Interest, Ratio and Proportion, Time and Work and in geometry we learn Quadrilaterals, Parallelograms, Construction of Quadrilaterals, Three-Dimensional Figures, Area of a Trapezium and a Polygon, Volume and Surface Area of Solids, Data Handling, Constructing and Interpreting Bar Graphs, Pie Charts, Probability, Graphs, etc……


If student follow math-only-math they can improve their knowledge by practicing the worksheets for 8th graders which will them to score in their exam.

 Set Theory

Sets Theory: Brief description on set theory and the important sets used in mathematics.

Representation of a Set: Definition with examples of statement form, roster form or tabular form, set builder form cardinal number of a set and the standard sets of numbers.

Types of Sets: Definition with examples of empty set or null set, singleton set, finite set, infinite set, cardinal number of a set, equivalent set and equal sets.

Finite Sets and Infinite Sets: Learn how to distinguish between finite set and infinite set with examples.

Power Set: Explanation on power sets will help us to get the basic concepts if sets with examples.

Problems on Union of Sets: Learn how to find the union of two or more sets and worked-out examples of operations on union of sets.

Problems on Intersection of Sets: Learn how to find the intersection of two or more sets and worked-out examples of operations on intersection of sets.

Difference of two Sets: Learn how to find the difference between the two sets and worked-out examples.

Complement of a Set: Definition of complement of a set and their properties with some worked-out examples.

Problems on Complement of a Set: Learn how to find the complement of two or more sets and worked-out examples of operations on complement of sets.

Problems on Operation on Sets: Learn how to find the union and intersection of two or more sets and worked-out examples of the two basic operations of sets.

Word Problems on Sets: Apply set operations to solve word problems involving the properties of union and intersection of sets.

Venn Diagrams in Different Situations: Learn how to use the Venn diagrams in different situations to find the different sets.

Relationship in Sets using Venn Diagram: Learn how to find the relationship of the union, intersection and difference of the two sets using Venn-diagram.

Union of Sets using Venn Diagram: Diagrammatic representation to find the union of two sets and their properties, worked-out examples.

Intersection of Sets using Venn Diagram: Diagrammatic representation to find the intersection of two sets and their properties, worked-out examples.

Disjoint of Sets using Venn Diagram: Learn how to represent the disjoint sets of union and intersection using Venn-Diagram.

Difference of Sets using Venn Diagram: Learn how to represent the difference between two sets using Venn-Diagram.

Examples on Venn Diagram: Learn how to use the basic concepts of sets for solving the different types of problems on Venn diagram.

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Math Practice Test on Function

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Is Zero a Rational Number?

Is Every Rational Number an Integer?

Is Every Rational Number a Fraction?

Positive Rational Number

Negative Rational Number

Equivalent Rational Numbers

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Rational Number in Different Forms

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Equality of Rational Numbers using Standard Form

Equality of Rational Numbers with Common Denominator

Equality of Rational Numbers using Cross Multiplication

Comparison of Rational Numbers

Rational Numbers in Ascending Order

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Representation of Rational Numbers on the Number Line

Rational Numbers on the Number Line

Addition of Rational Number with Same Denominator

Addition of Rational Number with Different Denominator

Addition of Rational Numbers

Properties of Addition of Rational Numbers

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Worksheet on Finding Rational Numbers between Two Rational Numbers

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Factorization of Perfect Square

Factorization of Perfect Square Trinomials

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Factorize the Difference of Two Squares

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Factorize the Trinomial ax^2 + bx + c

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H.C.F. of Polynomials by Division Method

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Relation Between H.C.F. and L.C.M. of Two Polynomials

Reduce Algebraic Fractions to its Lowest Term

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Worksheet on H.C.F. of Monomials

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Worksheet on H.C.F. and L.C.M. of Monomials

Worksheet on H.C.F. of Polynomials

Worksheet on L.C.M. of Polynomials

Worksheet on H.C.F. and L.C.M. of Polynomials

Worksheet on Reducing Algebraic Fractions

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Worksheet on Algebraic Fractions

Worksheet on Simplifying Algebraic Fractions

Equations

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Worksheet on Quadratic Equations

Percentage

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Two Objects Move in Same Direction

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Train Passes a Moving Object in the Same Direction

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Train Passes through a Pole

Train Passes through a Bridge

Two Trains Passes in the Same Direction

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Worksheet on Conversion of Units of Speed

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Worksheet on Relative Speed

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Simple Interest

What is Simple Interest?

Calculate Simple Interest

Practice Test on Simple Interest

Simple Interest - Worksheets

Simple Interest Worksheet

Compound Interest

Compound Interest

Compound Interest with Growing Principal

Compound Interest with Periodic Deductions

Compound Interest by Using Formula

Compound Interest when Interest is Compounded Yearly

Compound Interest when Interest is Compounded Half-Yearly

Compound Interest when Interest is Compounded Quarterly

Problems on Compound Interest

Variable Rate of Compound Interest

Difference of Compound Interest and Simple Interest

Practice Test on Compound Interest

Uniform Rate of Growth

Uniform Rate of Depreciation

Uniform Rate of Growth and Depreciation

Compound Interest - Worksheet

Worksheet on Compound Interest

Worksheet on Compound Interest when Interest is Compounded Half-Yearly

Worksheet on Compound Interest with Growing Principal

Worksheet on Compound Interest with Periodic Deductions

Worksheet on Variable Rate of Compound Interest

Worksheet on Difference of Compound Interest and Simple Interest

Worksheet on Uniform Rate of Growth

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Worksheet on Uniform Rate of Growth and Depreciation

Ratio and Proportion (Direct & Inverse Variation)

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