Started a run by reaching 200 m in 30 s. she then ran 300 m in 30 s. what was her acceleration?

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Problem:

A student is running in a track meet started a run by reaching 200m in 30 seconds.She then ran 300m in 30 seconds what was her acceleration? (using GRESA method).

Note:

Distance travelled is equal to 500 meters. Total time is equal to 60 seconds. We need to solve first the final velocity.

Solving for final velocity:

Vf = 500 m / 60 s

    = 8.33 m/s

Given Data:

t ( time ) = 60 s

Vi ( initial velocity ) = 0 m/s (from start)

Vf ( final velocity ) = 8.33 m/s

a ( acceleration ) = ? unknown

Solution:

We can use the formula (a = Vf - Vi / t) in order to solve for acceleration

a = Vf - Vi / t

  = 8.33 m/s - 0 m/s / 60 s

  = 8.33 m/s / 60 s

  = 0.14 m/s²

Answer:

The acceleration is equal to  0.14 m/s²

Kindly visit the link below:

brainly.ph/question/1193587

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  where did you get the 8,33m/s?

• ayan na din po ba yung mismong sagot?