What is the n of an hcl solution if 45.23 ml of it is required to titrate a 0.2505 sample of na2co3?

MODULE 8 ACTIVITY 2 INDIVIDUAL ACTIVITY ON ANACHEM LECPROBLEMS ON VOLUMETRIC ANALYSISInstruction: After studying the ppt on Volumetric Analysis and Module 8 answer the ffproblems.Use the following formula:1. C1V1 = C2V22. Nacid x Vacid = Nbase x Vbase3. %analyte = Ntitrant x Vtitrant x EqWt Analytex 100%wt. of sampleProblems:1. What volume of 0.2963 N H2SO4 is required to prepare 250. 0 mL of 0.1000 N H2SO4?2. What is the N of an HCl solution if 25.03 mL of it requires 29.07 mL of 0.1025 N NaOH fortitration?3. What is the N of an HCl solution if 45.23 mL of it is required to titrate a 0.2505 sample ofNa2CO3?4. A sample of soda ash (impure Na2CO3) is titrated with 0.5000 N H2SO4. If the sampleweighs 1.1000 g and requires 35.00 mL ofthe acid for complete neutralization, what is the%Na2CO3 in the ash assuming no other active component is present?At. Mass: Cl 35.45

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Sodium hydroxide, Acid Base Titration, Volumetric Analysis and Module

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A 0.156 g sample of sodium carbonate, Na2CO3, required 19.95 mL of an HCl solution to completely titrate the Na2CO3 . Na2CO3(aq) + 2 HCl(aq)→ 2 NaCl(aq) + CO2(g) + H2O What is the molarity of the HCl solution according to this trial?

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