A tank is filled with water to a height of 12.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 9.4 cm. What is the refractive index of water? If water is replaced by a liquid of refractive index 1.63 up to the same height, by what distance would the mircoscope have to be moved to focus on the needle again?
Case I: When tank is filled with water. Given, real depth = 12.5 cm; apparent depth = 9.4 cm Now, using the formula, μ = real depthapparent depth we have,Refractive index, μ = 12.59.4 = 1.33 Case II: When water in the tank is replaced by another liquid. Refractive index of liquid, μ = 1.63Real depth = 12.5 cmTherefore,apparent depth = real depthμ i.e., apparent depth = 12.51.63 = 7.67 cm Distance through which microscope has to be moved downward is = (9.4 – 7.67) cm = 1.73 cm. Open in App 24 |