If you're seeing this message, it means we're having trouble loading external resources on our website. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. Open in App Suggest Corrections 0 Q. We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is . What is the angle subtended at the centre of a circle of radius 6 cm by an arc of length 3 π cm?We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is . Write whether 245+32025on simplification gives a rational or an irrational number.Write the condition to be satisfied by q so that a rational number pq has a terminating decimal expansions.For what value of k, is −2 a zero of the polynomial 3x2 + 4x + 2k?What is the total number of factors of a prime number?Q. We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is . What is the angle subtended at the centre of a circle of radius 6 cm by an arc of length 3 π cm?We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is . Write whether 245+32025on simplification gives a rational or an irrational number.Write the condition to be satisfied by q so that a rational number pq has a terminating decimal expansions.For what value of k, is −2 a zero of the polynomial 3x2 + 4x + 2k?What is the total number of factors of a prime number?Q. We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is . What is the angle subtended at the centre of a circle of radius 6 cm by an arc of length 3 π cm?We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is . Write whether 245+32025on simplification gives a rational or an irrational number.Write the condition to be satisfied by q so that a rational number pq has a terminating decimal expansions.For what value of k, is −2 a zero of the polynomial 3x2 + 4x + 2k?What is the total number of factors of a prime number?Q. We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .
We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is . What is the angle subtended at the centre of a circle of radius 6 cm by an arc of length 3 π cm?We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is .We have We will find the angle subtended at the centre of a circle. Substituting the values we get, …… (1)Now we will simplify the equation (1) as below, Therefore, angle subtended at the centre of the circle is . Write whether 245+32025on simplification gives a rational or an irrational number.Write the condition to be satisfied by q so that a rational number pq has a terminating decimal expansions.For what value of k, is −2 a zero of the polynomial 3x2 + 4x + 2k?What is the total number of factors of a prime number? |