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Correct Answer: (Option A – 1) Explanation: n = 3, ℓ = 1, m = 0 Orbital is 3pz So only one orbital can be identified with these quantum numbers.
The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.
We know Energy of the incident radiation = Work function + KE of photoelectron Work function = Energy of the incident radiation - KE of photoelectron ..(1).Now energy of the incident radiation (E) = hv..(2)Substituting the values in eq. (2), we have Energy of incident radiation The potential applied gives the kinetic energy to the electron. Hence, the kinetic energy of the electron = 4.4 eV.Substituting the values in eq. (1), we have Work function = 4.83 eV - 0.35 eV = 4.48 eV Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Suggest Corrections 4 Text Solution 1234 Answer : A Solution : (a) Given : `n = 3, l = 1, m = 0` <br> Hence orbital is `3 p` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/A2Z_CHM_XI_C02_E01_317_S01.png" width="80%"> <br> Hence the number of orbital identified by `m = 0` can be one only. Text Solution 1234 Answer : A Solution : (a) The value of n=3 and l=1 suggests that it is a 3p-orbital while the value f `m_(l)=0` [magnetic quantum number ] shows that the given 3p-orbital is `3p_(z)` in nature. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_31Y_NEET_CHM_C02_E01_007_S01.png" width="80%"> <br> Hence, the maximum number of orbitals identified by the given quantum number is only 1, i.e. `3p_(z)`. |