When the sun s altitude changes from 30° to 60°, the length of the shadow of a tower decreases by 70m. What is the height of the tower?
Explanation: Let AD be the tower, BD be the initial shadow and CD be the final shadow.Given that BC = 70 m, $\angle$ABD = 30°, $\angle$ACD = 60°,Let CD = x, AD = hFrom the right $\triangle$ CDA, tan60°=$\dfrac{AD}{CD}$√3=$\dfrac{h}{x} $ ⋯(eq:1)From the right $\triangle$ BDA, tan30°=$\dfrac{AD}{BD}$$\dfrac{1}{\sqrt{3}}=\dfrac{h}{70+x} $ ⋯(eq:2)$\dfrac{eq:1}{eq:2}⇒\dfrac{\sqrt{3}}{\left( \dfrac{1}{\sqrt{3}} \right)}=\dfrac{\left( \dfrac{h}{x}\right)}{\left( \dfrac{h}{70+x}\right)}$⇒3=$\dfrac{70+x}{x}$⇒2x=70⇒x=35Substituting this value of x in eq:1, we have√3=$\dfrac{h}{35}$⇒h=35√3=35×1.73=60.55≈60.6
Next Question A person, standing exactly midway between two towers, observes the top of the two towers at angle of elevation of 22.5° and 67.5°. What is the ratio of the height of the taller tower to the height of the shorter tower? (Given that tan 22.5° = √2−1)No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Suggest Corrections |