What mass of glucose would you need to have 0.8 mol

118 What mass of glucose would you need (in g) to have 0.8 mol, given that the molar mass of glucose is 180 g mol-l? swered ut of 2.00 uestion Select one: 0.144 g 1.44 g 14.49 144 9

The molecular mass of glucose is about $180 \mathrm{g} / \mathrm{mol}$. If $45 \mathrm{g}$ of glucose is dissolved in water to make a final volume of $0.5 \mathrm{L},$ what is the molarity of the solution? a. $0.125 \mathrm{M}$ b. $0.25 \mathrm{M}$ c. $0.5 \mathrm{M}$ d. $1.0 \mathrm{M}$ e. $2.0 \mathrm{M}$

First of all, let's have a look what all is given in the problem. Given ish Equal solution of a strength. 10 Strength has given us 10 And mole she's given that is one grand mole. one g model of glucose. What we are supposed to find out, we have to find the volume in which this much g one g model of glucose will dissolve to give 10% of strength solution. That means we have to find the volume First of all. What does this? 10% means 10% of glucose solution means 10 dramas present. 10% of glucose solution Means 10 Grandma's present mullah march of glucose is Mueller myself, glucose, that is C six H 12 06 is 1 80 g per mole. From here we can calculate the number of moles that is given must by muller March Given masses 10 g molar masses one itty. So the number of moles will come around Then by 180. This many moles are present in 100 cc, 100 cc or 1000.1 liter. So from here we can say that for one model of glucose, volume required will be volume required. Mhm is .1 into 180 .1 and two 1 80 divided by then, And it will come around 1.8 L. hence the correct option is option number. The

In this problem we'll be solving for polarity. We'll be doing that by listing are known and unknown. Will be converting measurements as needed. And then we'll be able to solve first. Let's take a look at the question. In 45 g of glucose is dissolved into a final volume of 0.5 liters. What's the polarity? Okay. Let's take a look at some of the things we know. Well, we know the mass of the glucose. We've got 45 g of glucose. You've been given the molar mass of glucose as well. And that is 180 most. The other thing that we know is the final volume of the solution. Yeah, that's 0.5 liters. So those are really the three things that we know. Okay, unknown. What are we looking for? We are looking for the more clarity and we've already got our formula there on the page. So we are all set. So we've got her knowns and unknowns listed. Now let's take a look for any thing that we might need to convert. Our volume is already in leaders. So we won't need to convert that. The mass of glucose, however, is in grams. And we want that. We want to know how many moles of glucose we have. So we will want to convert the 45 g of glucose into moles. So let's go ahead and do that. Um, we will convert that. Okay, here 45 g of glucose. 180 g per mole 0.25 moles. Okay. And that is 0.25 moles of glucose. Now that we've converted as needed. We can use our formula, plug everything in and solve for the polarity. So for our formula, we know that the mola parity is equal to moles over the leaders. So here we've got the 0.25 moles of glucose. And we have a total final volume of 0.5 liters, giving us a final answer of a polarity of zero 0.5 right. And that is how we solve for the polarity of a solution.

Okay, so we need to convert molecules into crams. We're gonna start with our given amount, which, in this case, is 3.6 two times 10 to his rayford molecules. Um, of glucose. This six age? Well, six. Um, Okay, So the only thing that contains molecules only conversion factor with molecules in it is, um, avocados. Number seven multiplied by my conversion factor. So, in everyone, mole, there's 6.2 Tend to the 23rd molecules. It allows me to cancel out my units so I don't want moles of glucose. I want grams of glucose. I'm gonna multiply by the molar mass. So I went ahead and calculated the Mueller Mass. Which is 1 80.15 grams for everyone. Well of glucose and just, um, really quickly a reminder. Um, so you get that by adding up the muller methods of each so carbon. There are six carpets and carbon muller mass from the periodic table of 6.1 Um, hydrogen. There's 12 of them, and it's 1.8 and an oxygen. There's six of them in its 15 points and 99 Now, your your period table might be slightly different. Somehow it was rounded, Um, so your numbers might not be exactly but but like mine, but they should be pretty, like pretty Close said When you multiply those out and animal together, you should get, um, that 1 80.15 grams Permal and then that That's your conversion factor. Okay, so now that we've refreshed that, we've got our whole equation written out now, we just need to plug it in our calculator, and I actually just noticed. So my molecules of glucose is actually not times 10 to the two. It's time. 10. So the 24th and that will really affect our numbers. So I want to make sure I go in and fix that. Um, so when a plug in my calculator 3.62 times in the 24th and how I do it, I'm gonna hit divided by 6.2 times 10 to the 23rd times 1 80.15 And then that will give me an answer of 1083 0.29 grams of glucose. And this number is fine, except it doesn't. I'm take into account significant figures which, if you'll notice. Um, I should really be at three. So, um, toe do that effectively. I'm gonna go ahead and put it in scientific notation. So initially, that would be, um 108 And then we'd be done. But, um, when we got a zero and then so this would be if we left it as not, um, scientific notation. And then in scientific notation, we'd have one point. Oh, a times 10 the third, Gramps. So either of those answers are, um

Hey, guys. Latest problem 19 This problem says how many glucose molecules just a cell in Problem 18 contain eight symptoms whose concentration is also given now from problem 18. We had calculated the volume in Santa Cell and the whole American related as 5.23 multiplied right into the brush. 16 leader How we calculated that in problem 18 the diameter in Santos l is given, which is one micrometer. And while my perimeter means that one multiply, divide it into the ground minus 6 m. We know that the volume of this pair is four by three by RQ you know that are is going to our means radius radius This is going to die MIT and divided by two The diameter is Stephen. Therefore, we just insulted the diameter value here and buy is 3.14 and we calculated the volume and we got that 5.23 multiplied by the universe 19 immediately to convert media cute little we need to multiply the number by 1000 so we multiply by 1000 And what the volume movie Now from this problem, what we need to do we need to calculate What is the moles that can The concentration is given, You know that well, it's going to from Centrais Shin mhm multiplied by volume. You know that the uniform concentration is model and volumes, concentration volumes, unities leader and more elements that more of our little And when this little later will we lived with Mom and therefore we will calculate what is the number of moles and using the number of moles we can calculate. What is the number of molecules they want? A number of the first one again. Mhm. This is it going to do? We know that there is 6.23 multiplied by tempted about 23 molecules bar 11 Therefore the number of glucose monitor comes. Is it going to this number of molecules? Farm all mounted right by the one that we will get, say this month what we will get, which is a quality concentration on two primary funding. Now we have all the values we need to just report them. Mhm. The concentration is given by US $1 million. We need to convert it to a million dollars to Malange. Let's do that. You can work from many more too many to multiply dinner anniversary. Then we get a boner. Now we know that one arm. Use that more than one leader. Let's just write one religion instead of more live. And then when American. But it it is 0.23 multiplied, waiting to divorce 16 liters. Mhm negative 16 did. And then when we do this calculation, we will get 3.1 fine multiplied right into the power. Five. More like you. Mhm. Therefore, the number of glucose molecules, these 3.15 25.

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