CBSE Class 12
Calculate the mass of cane sugar and water required to prepare 250 g of 25% solution of cane sugar? Please explain this question in detail.
 Answer Hint: We know that mass percentage is one way to express concentration of a solution using the mass of solute and solution. Here, we have to use the formula of mass percentage, that is, ${\rm{Mass}}\% = \dfrac{{{\rm{Mass}}\,{\rm{of}}\,{\rm{solute}}}}{{{\rm{Mass}}\,{\rm{of}}\,{\rm{solution}}}} \times 100$. Complete step by step answer: We know that there are many ways of expressing concentration of a solution, such as, molarity, molality, volume percentage, ppm, mole fraction etc. Here, we have to use a mass percent formula to calculate the mass of solute and solvent.Given that mass of solution is 250 g and mass percent of the solution is 25%. Now, we have to use the formula of mass percent.Mass percent of sugarsolution=$\dfrac{{{\rm{Mass}}\,{\rm{of}}\,{\rm{sugar}}}}{{{\rm{Mass}}\,{\rm{of}}\,{\rm{solution}}}} \times 100$Now, we have to put the values of mass percent of sugar solution (25%) and mass of sugar solution (250 g) in the above equation.$ \Rightarrow 25 = \dfrac{{{\rm{Mass}}\,{\rm{of}}\,{\rm{sugar}}}}{{250}} \times 100$$ \Rightarrow {\rm{Mass}}\,{\rm{of}}\,{\rm{sugar = }}\dfrac{{25 \times 250}}{{100}} =62.5\,{\rm{g}}$Therefore, the mass of sugar in the solution is 62.5 g.Now, we have to calculate the mass of water in the solution. We know that, mass of solute and Solvent gives the total mass of the solution.The mass of solute (sugar) is 62.5 g and the mass of the solution is 250 g.Formula is, Mass of solute (sugar) + Mass of solvent (water)= Mass of solutionMass of water= Mass of solution- Mass of sugar$ \Rightarrow {\rm{Mass}}\,{\rm{of}}\,{\rm{water}} = 250\,{\rm{g}} - {\rm{62}}{\rm{.5}}\,{\rm{g}}= {\rm{187}}{\rm{.5}}\,{\rm{g}}$Therefore, the mass of water in the solution is 187.5 g. Note: Remember that molarity and molality both are used to measure concentration of a solution. Molarity is the moles of solute present in solution of one litre and molality is the moles of solute present in 1 kg of solvent.
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Asked by vekariyaparth61 | 16 May, 2022, 04:33: PM ANSWERED BY EXPERT Text Solution Solution : Mass percent `=("Mass of solute")/("Mass of solution")xx100` <br> Mass percent =25, Mass of solution = 250 g <br> `:. 25 = ("Mass of can sugar")/((250 g))xx100` <br> `:.` Mass of cane sugar `= (25 xx(250 g))/(100)=62.5 ,` Mass of water `= 250-62.5=187.5g`. |
What mass of cane sugar is required to prepare 250g of 25?
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