What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

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What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

Solution:

(i) 402

We know that, if we subtract the remainder from the number, we get a perfect square.

Here, we get the remainder 2. Therefore 2 must be subtracted from 402 to get a perfect square.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

\therefore402-2=400

Hence, the square root of 400 is 20.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

(ii) 1989

We know that, if we subtract the remainder from the number, we get a perfect square.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

Here, we get the remainder 53. Therefore 53must be subtracted from 1989 to get a perfect square.

\therefore1989-53=1936

Hence, the square root of 1936 is 44.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

(iii) 3250

We know that, if we subtract the remainder from the number, we get a perfect square.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

Here, we get the remainder 1. Therefore 1 must be subtracted from 3250 to get a perfect square.

\therefore3250-1=3249

Hence, the square root of 3249 is 57.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

(iv) 825

We know that, if we subtract the remainder from the number, we get a perfect square.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

Here, we get remainder 41. Therefore 41 must be subtracted from 825 to get a perfect square.

\therefore825-41=784

Hence, the square root of 784 is 28.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

(v) 4000

We know that, if we subtract the remainder from the number, we get a perfect square.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

Here, we get the remainder 31. Therefore 31 must be subtracted from 4000 to get a perfect square.

\therefore4000-31=3969

Hence, the square root of 3969 is 63.

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

What least number must be subtracted from 1000 to get a number exactly divisible by 123 select?

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Which least number should be subtracted from 1000 so that the difference is exactly divisible by 35

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