What is the molality of a solution prepared from 12.5 g kno3 and 75.0 g h2o?

What is the mass percent (m/m) of a solution containing 55 grams of calcium chloride, CaCl2, and 125 grams of water?
Remember to select an answer with the correct number of significant figures.

With this molality calculator you can quickly calculate the molality - one way of measuring the concentration of a solute in a solution (not to be confused with molarity). Simply type the number of moles of your solute substance and mass of the solvent and the tool will calculate the molality. If you don't know how many moles of a substrate you have, use the advanced mode to calculate it with the use of mass and molar mass of the compound. Are you still unsure what's the molality definition, its units and formula - or simply how to calculate molality step by step? Keep reading and you'll find the answer!

Molality, also called molal concentration, is defined as the amount of substance of solute, divided by the mass of the solvent m solvent:

Molality = nsolute / m solvent = msolute / (W solute * m solvent)

where

  • nsolute is amount of the solute (in moles)
  • msolvent is a mass of the solvent (in kg)
  • msolute is a mass of the solute (in g)
  • W solute is a molar mass of the solute (in g/mol).

The molality unit from SI system is mol/kg, sometimes the name molal is used (though it's considered obsolete).

Molality plays a significant role in calculating the ionic strength of a solution.

Molarity and molality are similar concepts - both are measures of the concentration of a solution. However, there is one main difference between those terms: molarity is expressed as the amount of substance per unit volume of solution, whereas molality defines the concentration as the amount of substance per unit mass of the solvent.

We've put all most important differences between those two terms into a short molarity vs molality table:

Molarity Molality
Definition Amount of substance (in moles) divided by the volume (in litres) of the solution Amount of substance (in moles) divided by the mass (in kg) of the solvent
Symbol M m or b
Unit mol/L mol/kg
Temperature and pressure dependent independent
Usage more popular, practical to use in the lab, faster and easier accurate but rarely used

To change between molarity and molality you can use the following relation:

M = m * d / (1 + (m * W))

where

  • M - molarity
  • m - molality
  • W - molar mass of the solute
  • d - mass density of the solution

Let's show on the example how to calculate molality:

  1. Choose your substance. Let's assume it's table salt - sodium chloride (NaCl).
  2. Calculate its molar mass. For sodium chloride it's equal to 58.44 g/mol (as Na = 22.99 g/mol and Cl = 35.45 g/mol).
  3. Convert grams to moles. Use the formula moles = mass of solute / molar mass. Assume we want to dissolve 70.128 grams of salt in 1.5 kg of water. so moles NaCl = 70.128 g / (58.44 g/mol) = 1.2 mol.
  4. Plug moles value and the mass of the solvent into the molality formula. Divide 1.2 mol by 1.5 kg, and you'll find out that the molality of the NaCl solution is 0.8 molal (in standard molality units: 0.8 mol/kg).
  5. Or save yourself some time and use our molality calculator (choose an advance mode to enter also the molar mass and solute mass).

  • Now the #"moles of solute"# are a constant. The volume of solution MAY change substantially with increasing or decreasing temperature. In some calculations #"molality"# is used in preference, which is defined by the quotient....

    #"molality"="moles of solute"/"kilograms of solvent"#

    ....this is temperature independent, and at lower concentrations, #"molarity"-="molality"#.

  • To get the molarity, you divide the moles of solute by the litres of solution.

    #"Molarity" = "moles of solute"/"litres of solution"#

    For example, a 0.25 mol/L NaOH solution contains 0.25 mol of sodium hydroxide in every litre of solution.

    To calculate the molarity of a solution, you need to know the number of moles of solute and the total volume of the solution.

    To calculate molarity:

    1. Calculate the number of moles of solute present.
    2. Calculate the number of litres of solution present.
    3. Divide the number of moles of solute by the number of litres of solution.

    EXAMPLE:

    What is the molarity of a solution prepared by dissolving 15.0 g of NaOH in enough water to make a total of 225 mL of solution?

    Solution:

    1 mol of NaOH has a mass of 40.00 g, so

    #"Moles of NaOH" = 15.0 cancel("g NaOH") × "1 mol NaOH"/(40.00 cancel("g NaOH")) = "0.375 mol NaOH"#

    #"Litres of solution" = 225 cancel("mL soln") × "1 L soln"/(1000 cancel("mL soln")) = "0.225 L soln"#

    #"Molarity" = "moles of solute"/"litres of solution" = "0.375 mol"/"0.225 L" = "1.67 mol/L"#

    Some students prefer to use a "molarity triangle".

    What is the molality of a solution prepared from 12.5 g kno3 and 75.0 g h2o?

    It summarizes the molarity formulas as

    #"Moles" = "molarity × litres"#

    #"Molarity" = "moles"/"litres"#

    #"Litres" = "moles"/"molarity"#