What is the angle of elevation of the sun when the length of the shadow of a 16 m high pole is 48 m?

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Given:

Length of the pole is 15m and length of the shadow of the pole is 15√3 m

Concept Used:

tanθ = Height/Base

Calculation:

Let, θ be the angle of elevation

Here,

tanθ = AB/BC

⇒ tanθ = 15/15√3

⇒ tanθ = 1/√3

⇒ tanθ = tan30°

⇒ θ = 30°

∴ The angle of elevation of the sun is 30°.

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