Text Solution
Solution : <img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XII_V01_C02_SLV_012_S01.png" width="80%"> <br> To find the equivalent resistance between the points a and b, we assume that current is entering the junction a, Since all the resistances in the outside loop are the same `(1Omega)`, the current in the branches ac and ad must be equal. So the electric potential at the point c and d is the same hence no current flows into `5Omega` resistance. It implies that the `5Omega` has no role in determining the equivalent resistance and it can be removed. So the circuit is simplified as shown in the figure. <br> <img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XII_V01_C02_SLV_012_S02.png" width="80%"> <br> The equivalent resistance of the circuit between a and b is `R_(eq)=1Omega`.
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