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If temperature of gas increases from 27°C to 927°C, the kinetic energy will be Options(a) double (b) half the initial value (c) one fourth (d) four times Correct Answer:four times Explanation:T₁ = 27⁰C =300K T₂ =927⁰C =1200K V(rms)( root mean square velocity )= √3RT/M KE₁ = 2/1×m×V² rms KE₂= 2/1×m× 3R×1200/m =4KE₁ . Related Questions:No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today!
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