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Solve the following example.
The velocity of a car increase from 54 km/hr to 72 km/hr. How much is the work done if the mass of the car is 1500 kg?
Here, v = 72 km/h = 20 m/s, u = 54 km/h = 15 m/s, m = 1500 kgWork done by the car = Change in kinetic energy of the cari.e. `W = K.E_f - K.E_i``W = 1/2 xx m xx v^2 - 1/2 xx m xx u^2 = 1/2 xx m(v^2 - u^2)`
= `1/2 xx 1500 (20^2 - 15^2)` = 131250 J
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