What is the smallest number by which 6750 must be divided so that the quotient is a perfect cube?

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  • What is the smallest number by which 1715 should be divided so that the quotient is a perfect square cube?
  • What is the least number by which 6750 must be divided so the quotient is perfect cube?
  • What is the smallest number by which 6912 must be divided to make it a perfect cube?
  • Is 6750 a perfect cube?


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Prime factorisation of 1715 = 5*7*7*7
The smallest no. will be 5

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Prime factorisation of 1715 = 5*7*7*7
The smallest no. will be 5

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(i) We have,

1536 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3

After grouping the prime factors in triplets, it’s seen that one factor 3 is left without grouping.

1536 = (2 × 2 × 2) × (2 × 2 × 2) × (2 × 2 × 2) × 3

So, in order to make it a perfect cube, it must be divided by 3.

Thus, the smallest number by which 1536 must be divided to obtain a perfect cube is 3.

(ii) We have,

10985 = 5 × 13 × 13 × 13

After grouping the prime factors in triplet, it’s seen that one factor 5 is left without grouping.

10985 = 5 × (13 × 13 × 13)

So, it must be divided by 5 in order to get a perfect cube.

Thus, the required smallest number is 5.

(iii) We have,

28672 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 7

After grouping the prime factors in triplets, it’s seen that one factor 7 is left without grouping.

28672 = (2 × 2 × 2) × (2 × 2 × 2) × (2 × 2 × 2) × (2 × 2 × 2) × 7

So, it must be divided by 7 in order to get a perfect cube.

Thus, the required smallest number is 7.

(iv) 13718 = 2 × 19 × 19 × 19

After grouping the prime factors in triplets, it’s seen that one factor 2 is left without grouping.

13718 = 2 × (19 × 19 × 19)

So, it must be divided by 2 in order to get a perfect cube.

Thus, the required smallest number is 2.

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Prime factorisation of 1715 = 5*7*7*7
The smallest no. will be 5

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What is the smallest number by which 1715 should be divided so that the quotient is a perfect square cube?

∴ We need to divide it by 5, then it becomes cube of 7 i.e 343.

What is the least number by which 6750 must be divided so the quotient is perfect cube?

Answer: 2 is the smallest number by which 6750 must be divided to get a perfect cube. The perfect cube number is = 3375 and the cube root is 15.

What is the smallest number by which 6912 must be divided to make it a perfect cube?

To do: To find the smallest number by which 6912 must be divided so that the number formed is a perfect cube. Therefore, we should divide 6912 by 22=4 2 2 = 4 , the smallest number to get 1728 which is a cube of 12 .

Is 6750 a perfect cube?

Step-by-step explanation: Since 2 is left unpaired, 6750 should be divided by 2 to make it a perfect cube.

What is the smallest number by which 6912 must be divided so that the quotient obtained will have a perfect cube root?

Given: A number 6912 . To do: To find the smallest number by which 6912 must be divided so that the number formed is a perfect cube. Therefore, we should divide 6912 by 22=4 2 2 = 4 , the smallest number to get 1728 which is a cube of 12 .

What is the smallest number by which 6750 must be multiplied so that the product is a perfect cube?

Hence, the smallest number by which 675 must be multiplied to obtain a perfect cube is 5.

What is the smallest number that you must multiply 6750 by in order to get a perfect square which is greater than 6750?

30 is the smallest number which multiplied to 6750 to make a perfect square.

What is the smallest number by which 8640 must be divided so that the?

Hence, 5 is the smallest number by which 8640 must be divided, so that the quotient is a perfect cube. Was this answer helpful?