What is the number of 5 digit numbers formed with 0 1 2 3 4 without any repetition of digits?

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Solution:

Option (A) 216 is correct

Explanation:

Using digits $0,1,2,4,5$ the 5-digit numbers that can be formed

$$\begin{tabular}{|l|l|l|l|l|} \hline 4 & 4 & 3 & 2 & 1 \\ \hline

\end{tabular}$$

$4 \times 4 \times 3 \times 2 \times 1=96$

Five digit nos. that can be formed using digits $1,2,3,4,5=5 !$

The total number of ways $=5 !+96$

$=216$

As a result, Option (A) 216 is the correct answer.

The number of 5 digit numbers without repetition using digits 0,1,2,3,4,5 such that they are even

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Text Solution

244896120

Answer : C

Solution : To make a 5 digit number, 0 can not come in the bagining. So, it can be filled in 4 ways. Rest of the places can be filled in 4! Ways. So total number of digit formed `= 4 xx 4! = 4 xx 24 = 96`