Hi numan,
As Molarity= moles of solute/ volume of solution(liters)
M= 5.85*1000/((23+35.5)*500)=0.2M
If you have any further query, feel free to ask.
Hello student,
The formula for molarity M is
M = mol v
The moles of sodium chloride is 5.85 58.4 ≈ 0.1 mol
The volume of water is 0.5 l
So
M = mol v = 0.1 0.5 = 0.2 M
Cheers!
Apply
Job Assurance with HCL | Stipend of INR 10,000 per month | Higher education* with BITS Pilani or SASTRA University
The Global Study Abroad Fair ...
ApplyMeet with prestigious universities from around the world | Registrations are now open for the Autumn 2022 fair
Apply
Engineering Prep Combo from Careers360
Apply
JEE Main Subscription from Careers360
Apply
NEET Subscription from Careers360
Reva University, Bangalore - ...
REVA University is Ranked 6th among universities in India by IIRF | Highest CTC 36 LPA
View All Application Forms
150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books
Text Solution
Solution : `n_("sucrose")=(mass)_("sucrose")/("molar mass")` <br> `=(3.42 g)/(342 g mol^(-1))=0.01 mol` <br> Since the density of water is `1.00 g mL^(-1)`, we can find the mass of water as follows: <br> `d_(H_(2)O)=m_(H_(2)O)/V_(H_(2)O)` <br> or `m_(H_(2)O)=(d_(H_(2)O))(V_(H_(2)O))` <br> `=(1.00 g mL^(-1))(50.0 mL)` <br> `=50.0 g` <br> Thus, the molality of the solution is <br> `Molality=n_("sucrose")/g_(H_(2)O)xx(1000 g)/(kg)` <br> `=(0.01 mol)/(50.0 g)xx(1000 g)/(kg)` <br> `=0.2 m`
Solution of 'A' containing 3.42 g of it in 100 cm3 of water is found to be isotonic with a 6.84% `("w"/"V")` solution of sucrose, what is the molar mass of 'A'? (At. wt: C = 12, H = 1, O = 16)
171
Explanation:
Molecular mass of Sucrose = C12H22O11 = 342 g mol-1
Molarity of Sucrose Solution = `("w" xx 1000)/("M" xx "V"_("cm"^3)) = (6.84 xx 1000)/(342 xx 100)` = 0.2 M
∴ Molarity of 'A' = molarity of sucrose solution= 0.2 M
Molarity of 'A' solution = `("w" xx 1000)/("M" xx 100)`
0.2 = `(3.42 xx 1000)/("M" xx 100)`
M = `34.2/0.2` = 171 g mol-1
Concept: Osmotic Pressure
Is there an error in this question or solution?
Molarity of a solution that has 3.42 g sucrose in 500 mL solution is.A. 0.2B. 0.02C. 2D. 0.342
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
No worries! We‘ve got your back. Try BYJU‘S free classes today!
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Suggest Corrections
1