# What is the molarity of the solution obtained by dissolving 3.42 gram of sucrose in hundred Centimetre cube of the solution?

 Hi numan, As Molarity= moles of solute/ volume of solution(liters) M=  5.85*1000/((23+35.5)*500)=0.2M If you have any further query, feel free to ask. Hello student, The formula for molarity M is M = mol v The moles of sodium chloride is 5.85 58.4 ≈ 0.1 mol The volume of water is 0.5 l So M = mol v = 0.1 0.5 = 0.2 M Cheers! Apply Job Assurance with HCL | Stipend of INR 10,000 per month | Higher education* with BITS Pilani or SASTRA University The Global Study Abroad Fair ... Apply Meet with prestigious universities from around the world | Registrations are now open for the Autumn 2022 fair Apply Engineering Prep Combo from Careers360 Apply JEE Main Subscription from Careers360 Apply NEET Subscription from Careers360 Reva University, Bangalore - ... Apply REVA University is Ranked 6th among universities in India by IIRF | Highest CTC 36 LPA View All Application Forms 150M+ Students 30,000+ Colleges 500+ Exams 1500+ E-books Text SolutionSolution : n_("sucrose")=(mass)_("sucrose")/("molar mass")
=(3.42 g)/(342 g mol^(-1))=0.01 mol
Since the density of water is 1.00 g mL^(-1), we can find the mass of water as follows:
d_(H_(2)O)=m_(H_(2)O)/V_(H_(2)O)
or m_(H_(2)O)=(d_(H_(2)O))(V_(H_(2)O))
=(1.00 g mL^(-1))(50.0 mL)
=50.0 g
Thus, the molality of the solution is
Molality=n_("sucrose")/g_(H_(2)O)xx(1000 g)/(kg)
=(0.01 mol)/(50.0 g)xx(1000 g)/(kg)
=0.2 m Solution of 'A' containing 3.42 g of it in 100 cm3 of water is found to be isotonic with a 6.84% ("w"/"V") solution of sucrose, what is the molar mass of 'A'? (At. wt: C = 12, H = 1, O = 16)171 Explanation: Molecular mass of Sucrose = C12H22O11 = 342 g mol-1 Molarity of Sucrose Solution = ("w" xx 1000)/("M" xx "V"_("cm"^3)) = (6.84 xx 1000)/(342 xx 100) = 0.2 M ∴ Molarity of 'A' = molarity of sucrose solution= 0.2 M Molarity of 'A' solution = ("w" xx 1000)/("M" xx 100) 0.2 = (3.42 xx 1000)/("M" xx 100) M = 34.2/0.2 = 171 g mol-1 Concept: Osmotic Pressure  Is there an error in this question or solution? Molarity of a solution that has 3.42 g sucrose in 500 mL solution is.A. 0.2B. 0.02C. 2D. 0.342No worries! We‘ve got your back. Try BYJU‘S free classes today!Right on! Give the BNAT exam to get a 100% scholarship for BYJUS coursesNo worries! We‘ve got your back. Try BYJU‘S free classes today!No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in AppSuggest Corrections1