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Correct Answer: (Option A – 1)
Explanation:
n = 3, ℓ = 1, m = 0
Orbital is 3pz
So only one orbital can be identified with these quantum numbers.
The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.
We know Energy of the incident radiation = Work function + KE of photoelectron
Work function = Energy of the incident
radiation - KE of photoelectron ..(1).Now energy of the incident radiation (E) = hv
What is the maximum number of orbitals that can be identified with the following quantum numbers?n=3,l=+1,ml =0
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Text Solution
1234
Answer : A
Solution : (a) Given : `n = 3, l = 1, m = 0` <br> Hence orbital is `3 p` <br> <img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/A2Z_CHM_XI_C02_E01_317_S01.png" width="80%"> <br> Hence the number of orbital identified by `m = 0` can be one only.
Text Solution
1234
Answer : A
Solution : (a) The value of n=3 and l=1 suggests that it is a 3p-orbital while the value f `m_(l)=0` [magnetic quantum number ] shows that the given 3p-orbital is `3p_(z)` in nature. <br> <img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_31Y_NEET_CHM_C02_E01_007_S01.png" width="80%"> <br> Hence, the maximum number of orbitals identified by the given quantum number is only 1, i.e. `3p_(z)`.