What happens to the gravitational force between two objects when the distance between them is halved class 9?

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`F = (GMm)/r^2`where,F − gravitational forceG − gravitational constantM − mass of the earthm − mass of object

r − distance

(i).  r = doubled`F = (GMm)/r^2` keeping everything constant i.e. G, M, m= `(GMm)/(2r)^2`= `(GMm)/(4r^2)`

F becomes one-fourth.

(ii) r = halved`F = (GMm)/r^2`  keeping everything constant i.e. G, M, m= `(GMm)/(1/(2r))^2`= `(GMm)/(1/(4r))^2`= `(4GM  m)/(r^2)`

F becomes four times the original.