Total number of spectral lines emitted when an electron jumps from n=5 to n=1 in hydrogen atom is

Answer

Verified

Hint :In order to solve this question we must know few basic information like what is meant by spectral lines. Spectral series are said to be the set of wavelengths arranged in a sequential fashion which characterizes light or any electromagnetic radiation emitted by the energised atoms.

Complete Step By Step Answer:

Hydrogen atom is said to be the simplest atomic system found in nature, thus it produces the simplest of the spectral series.When electrons de-excite from higher energy level ( $ n_2 $ ) to lower energy level ( $ n_1 $ ) in atomic sample, then number of spectral line observed in the spectrum is given by the formula; $ Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = \dfrac{{\left( {n_2 - n_1} \right)\left( {n_2 - n_1 + 1} \right)}}{2} $ Since it is given in the question that in hydrogen atom electron jumps from $ n_2 = 5\; $ to $ n_1 = 1\; $ Therefore the total no of the spectral line is found to be; $ Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = \dfrac{{\left( {5 - 1} \right)\left( {5 - 1 + 1} \right)}}{2} $  $ Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = 10 $ So, the ten lines are; $ 5 \to 4,5 \to 3,5 \to 2,5 \to 1,4 \to 3,4 \to 2,4 \to 1,3 \to 2,3 \to 1,2 \to 1\; $ are possible in this case.Balmer series is displayed when electron transition takes place from higher energy states ( $ {{\mathbf{n}}_{\mathbf{h}}} = {\mathbf{3}},{\mathbf{4}},{\mathbf{5}},{\mathbf{6}},{\mathbf{7}}, \ldots $ ) to $ {{\mathbf{n}}_{\mathbf{l}}} = {\mathbf{2}} $ energy state. For Balmer series, $ {n_l} = 2 $ and $ {n_h} = 3,4,5 $ Thus,  $ 5 \to 2,4 \to 2,3 \to 2\; $ it shows three lines lie in the visible region. Hence the final answer is three spectral lines lie in the visible region for the hydrogen atom when electrons jump from $ n_2 = 5\; $ to $ n_1 = 1\; $ in the visible region.

Note :

All the wavelength of the Balmer series falls in the visible part of the electromagnetic spectrum( $ 400nm{\text{ }}to{\text{ }}740nm $ ). Other series are lyman series, paschen series, bracket series, pfund series, Humphreys series. The series is observed at a higher wavelength. The spectral lines are extremely faint and widely spread out. They correspond to highly rare atomic events.

How many spectral line will be observed when an electron jumps from n=5 to n=1 in the visible line spectra of H spectrum?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Suggest Corrections

5

Última postagem

Tag