# How many ways can you distribute 10 identical balls into two non identical boxes so none are empty?

 In how many ways can you distribute \$\$10\$\$ identical balls, into two non-identical boxes so that none are empty? A\$\$2\$\$ B\$\$8\$\$ C\$\$9\$\$ D\$\$10\$\$ 10 identical balls into two non-identical boxes as follows:\$\$(1,9),(2,8),(3,7),(4,6),(5,5),(6,4),(7,3),(8,2),(9,1)\$\$ In 9 ways 10 identical balls into two boxes can be distributed. In order to continue enjoying our site, we ask that you confirm your identity as a human. Thank you very much for your cooperation. \$\begingroup\$ In how many ways can I distribute $$100$$ identical balls into $$6$$ different boxes so that no box is left empty and every box contains even number of elements? Firstly, I placed $$2$$ balls in every box, which covers the condition that no box is left empty and since they all have to contain even number of elements I chose $$2$$ balls. Now there are $$88$$ balls left which I have to distribute. I just don't know how to cover the condition that every box should have even number of elements? Can I for example, look at two balls as "one" ball, and distribute the "$$44$$" balls into $$6$$ boxes? Then I could use Stirling number of the second kind... \$\endgroup\$