For what value of k the following system of equations kx + 2y = 3 3x + 6y = 10 has a unique solution

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Here $a_1=k,b_1=-2,a_2=3,b_2=1$.

$\frac{k}{3}\ne \frac{-2}{1}$

$k\ne -6$

(d) $k\ne -6$

(d) all real values except -6

The given equations are
kx + 2y = 3
3x + 6y = 10For a unique solution,`a_1/a_2 ≠ b_1/b_2`

Where a1= k, a2 = 3, b1 = 2, b2 = 6.

For all values of k except 1, the given linear equations will have a unique solution.