Copyright 2022 - wordunscrambler.net is not affiliated with SCRABBLE®, Mattel, Spear, Hasbro, or Zynga with Friends in any way
80 Questions 80 Marks 45 Mins
Concept: If we subtract the arrangements in which all 3 ‘E’ come together from total arrangement then we will get the required arrangements. Formula used: Arrangement of n letters of a word if no two letters repeat itself = n! Arrangement of n letters of a word if a word repeats itself x times = n!/x! Calculation: In word “SENTENCE” letter ‘E’ repeats 3 times and Letter ‘N’ repeats 2 times So total possible arrangement = 8!/(3! × 2!) Arrangement in which all 3 ‘E’ comes together = 6!/2! Now the required arrangement = 8!/(3! × 2!) – 6!/2! = 3360 - 360 = 3000 ∴ Required arrangement = 3000 India’s #1 Learning Platform Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes Trusted by 3.4 Crore+ Students |