Applying the law of cosines solve the following triangles. round to the nearest hundredth

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\( A = \cos^{-1} \left[ \dfrac{b^2+c^2-a^2}{2bc} \right]\)

R = radius of circumscribed circle

*Length units are for your reference-only since the value of the resulting lengths will always be the same no matter what the units are.

Calculator Use

Uses the law of cosines to calculate unknown angles or sides of a triangle. In order to calculate the unknown values you must enter 3 known values.

To calculate any angle, A, B or C, enter 3 side lengths a, b and c.  This is the same calculation as Side-Side-Side (SSS) Theorem. To calculate side a for example, enter the opposite angle A and the two other adjacent sides b and c. Using different forms of the law of cosines we can calculate all of the other unknown angles or sides. This is the same calculation as Side-Angle-Side (SAS) Theorem.

Law of Cosines

If a, b and c are the lengths of the legs of a triangle opposite to the angles A, B and C respectively; then the law of cosines states:

\( a^2 = b^2 + c^2 - 2bc \cos A \)

\( b^2 = a^2 + c^2 - 2ac \cos B \)

\( c^2 = a^2 + b^2 - 2ab \cos C \)

Law of Cosines solving for sides a, b, and c

\( a = \sqrt{b^2 + c^2 - 2bc \cos A } \)

\( b = \sqrt{a^2 + c^2 - 2ac \cos B } \)

\( c = \sqrt{a^2 + b^2 - 2ab \cos C } \)

Law of Cosines solving for angles A, B, and C

\( A = \cos^{-1} \left[ \dfrac{b^2+c^2-a^2}{2bc} \right] \)

\( B = \cos^{-1} \left[ \dfrac{a^2+c^2-b^2}{2ac} \right] \)

\( C = \cos^{-1} \left[ \dfrac{a^2+b^2-c^2}{2ab} \right] \)

Triangle Characteristics

Triangle perimeter, P = a + b + c

Triangle semi-perimeter, s = 0.5 * (a + b + c)

Triangle area, K = √[ s*(s-a)*(s-b)*(s-c)]

Radius of inscribed circle in the triangle, r = √[ (s-a)*(s-b)*(s-c) / s ]

Radius of circumscribed circle around triangle, R = (abc) / (4K)

References/ Further Reading

Weisstein, Eric W. "Law of Cosines" From MathWorld-- A Wolfram Web Resource. Law of Cosines.

Zwillinger, Daniel (Editor-in-Chief). CRC Standard Mathematical Tables and Formulae, 31st Edition New York, NY: CRC Press, p. 512, 2003.

http://hyperphysics.phy-astr.gsu.edu/hbase/lcos.html

http://hyperphysics.phy-astr.gsu.edu/hbase/lsin.html

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Answer:

IT ALREADY HAS SOLUTION HOPE IT HELPS(BRAINLIEST IF IT HELPS YOU) CORRECT ME IF IM WRONG:)

Step-by-step explanation:

#CARRYONLEARNING

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  Learning Task 3: Solve each triangle using the Law of Cosine. Round lengths to thenearest tenths and angle measures to the nearest degree.1. a = 11, b = 14, 2C = 1050

  Find: c, 2A, and 2B

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