In order to continue enjoying our site, we ask that you confirm your identity as a human. Thank you very much for your cooperation. Oftentimes, math problems will require that you know more than one concept. Sometimes, you’ll have to know the difference between an integer and a number in order to get the question right. Below, I’ve combined prime numbers with probability, two subjects already covered in this blog. The question below isn’t easy and actually takes a little bit of work. Let’s see if you can crack it. What is the probability that the sum of two rolled dice will equal a prime number? (A) 1/3 (B) 5/36 (C) 2/9 (D) 13/36 (E) 5/12 First let’s list the prime numbers that pertain to this problem.
The pertinent prime numbers are 2, 3, 5, 7, and 11. Notice I stopped at 11. Why? Well, the greatest number you can roll on two six-sided dice is 12. Next, we have to remember this is a probability question. Therefore, we have to divide the number of total outcomes by the number of desired outcomes. First, let’s find the number of desired outcomes. To do this, we have to make sure that each desired outcome conforms to the problem, i.e. how many different ways can we sum two dice to get a prime. Let’s start with 2. There is only one way to roll a 2, and that is with a 1 and a 1. Therefore, we have one desired outcome. What about the number 3? Well, we can get 2,1 and 1,2, or two possible ways. Mind you, to do this problem you will have to make sure you write down each outcome. Do not try to do this in your head, for you’ll most likely get the problem wrong and induce dizziness. Next we have the number 5, which we can get by rolling the following combinations: 1,4 4,1 2,3 3,2 We add these four possible outcomes to the prior three, giving us a total of 7. Next, we look to see which numbers sum to 7 and find a total of six possibilities. 1,6 2,5 3,4 4,3 5,2 6,1 Our total is now 13. Finally, don’t forget 11 as final prime number. 6,5 5,6 We add these two possibilities to the 13 possibilities, giving us a total of 15. Finally, we want to find the total number of outcomes. Remember, we divided the total outcomes by the total number of desired outcomes, which we just found out was 15. The total number of outcomes equals the number of different ways we can roll two six-sided dice. We find this number by multiplying 6 x 6. The logic is there are six sides to each die, so for each number on one die you can pair with six different numbers on the other die. Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12 (E). More from MagooshOpen in App Suggest Corrections 1
Solution: Sample space of rolling of 2 dice is as below, S = {(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6) (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)} n(S) = 36 Let A = sum of numbers is 7 = { (1, 6)(2, 5)(3, 4) (4, 3) (5, 2) (6, 1)} n(A) = 6 P (Sum of numbers is 7) = n(A) / n(S) = 6/36 = 1/6 Therefore, the probability of rolling two dice and getting a sum of 7 is 1/6. Summary: The probability of rolling two dice and getting a sum of 7 is 1/6. |
A pair of dice is rolled, find the probability that the sum is prime number or less than 7.
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